Matematică
mconyta
11

cine ma poate ajuta cu exercitiul 14?? Dau coroana!!! P.S. AM NEVOIE DE REZOLVARE!!! MULTUMESC...

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(2) Răspunsuri
Ymirchan

Am scris ... ca sa nu mai rescriu ex. '' ^ ''=''la puterea'' steluta reprezinta inmultirea b)...=6^20-6^23:6^3=6^20-6^20=0 c)...=24^18:24^16=24^2 d)...=3^38-3^57=3^38(1-3^19) e)...=2^27:2^10=2^17 f)...=5^64-5^12=5^12(5^52-1)

britny

14. b)3^20*2^20-6^23:6^3=(3*2)*20:6^23-3=6^20-6^20=0  c)2^18*12^18:(6^16*4^16)=(2*12)^!8:(6*4)^16=24^18:24^16=24^18-16=24^2=576 d)75^38:25^38-(3^19)^2=(75:25)^38-3^19*2=3^38-3^38=o e)26^37:13^27:2^5^2=(26:13)^27:2^25=2^27:2^25=2^27-25=2^2=4 f)10^64:2^64-5^4^3=(10:2)^64-5^64=5^64-5^64=0

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