Matematică
beniboxioru
21

calculeaza efectuand mai intai exercitile din paranteze 3×(4:2)= (3×4):2= 5×(4×7)= (5×4)+(5×7)= 7×(6-3)= (7×6)-(7×3)= (35+12)+6:3= 38+(12+40:8)= (99-35)+24+6×6= 27+27:9+(20:4:5+12)= 28+(7×6-24:6)+14= 33-3+(16:4:2×9+11)= 25+(11+7×7)+(25-3×6)= 56:7:2+(40:5:4:2+3)= va rog ajutor

+2
(1) Răspunsuri
violetamanda

6;6,150;55;21;21;49;55;124,42;80;59;92;8

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