Matematică
iruncik
15

am nevoie de ajutor cine ma ajuta cu ex 13 a si b va rog mult nu stiu cum sa le rezolv ,multumesc

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(1) Răspunsuri
andreeaiuli113

[latex]13.a)\frac{5\sqrt{2}}{2\sqrt5}+\frac{3}{\sqrt10}-\frac{2\sqrt5}{5\sqrt2}-\frac{3\sqrt5}{\sqrt8}=\\ \frac{5\sqrt10}{10}+\frac{3\sqrt10}{10}-\frac{2\sqrt10}{10}-\frac{3\sqrt5}{2\sqrt2}=\\ \frac{6\sqrt10}{10}-\frac{3\sqrt10}{4}=\\ \frac{3\sqrt 10}{5}-\frac{3\sqrt10}{4}=\frac{-3\sqrt10}{20} [/latex] [latex]b)\frac{2}{\sqrt6}+\frac{3\sqrt2}{2\sqrt3}-(\frac{2\sqrt{3}}{3\sqrt2}+\frac{8\sqrt2}{\sqrt27})=\\ \frac{2\sqrt6}{6}+\frac{3\sqrt6}{6}-\frac{2\sqrt6}{6}-\frac{8\sqrt2}{3\sqrt3}=\\ \frac{\sqrt6}{2}-\frac{8\sqrt6}{9}=\frac{\sqrt6}{18}[/latex]

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