Matemática
mariaclaraap
14

resolva as expressões numéricas abaixo a) 80+{5+[ (8+12)+(13+12)]+10}= b) 58+[48-(31-10)+15]= c) 38-{(51-15)+[5+(3-1)]-10}= d) [9+(585-15x6)] /56= e) [30-(17-8)x3+25]/7= f) 3-2x[3+(4-5)x3]=

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(1) Respostas
maandymoreira

A = 80+{5+[(8+12)+(13+12)]+10} 80 + { 5 + [20 +25] + 10 } 80 + { 5 + 45 + 10 } 80 + 60 140 B = 58 + [48 - (31 - 10) + 15] 58 + [48 - 21 + 15] 58 + [27 + 15] 58 + 42 100 C = 38-{36+[5+2]-10} = 38-{36+7-10}= 38-33 = 5 D = [9+(585-90)]/56= [9+495]/56= 504/56= 9 E = [30-(17-8).3+25]:7 [30 - (9).3 + 25 ]:7 [30 - 27 + 25 ]:7 28 : 7 = 4

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