Matemática
AnaClaudiaPereira
9

Preciso Das Respostas Dessas Alguém Sabe?

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(1) Respostas
RodrigoM

[latex]a) \\ (x+2)^2+x=0 \\ \\ x^2+4x+4+x=0 \\ \\ x^2+5x+4=0 \\ \\ delta=25-4.4=25-16=9 \\ \\ \sqrt{delta} = \sqrt{9} =3 \\ \\ x_{1} = \frac{-5+3}{2} = -1 \\ \\ x_{2} = \frac{-5-3}{2} -4[/latex] S={-4,-1} [latex]b) \\ 3x^2=2(x-1)^2+3 \\ \\ 3x^2=2(x^2-2x+1)+3 \\ \\ 3x^2=2x^2-4x+2+3 \\ \\ 3x^2-2x^2+4x-5=0 \\ \\ x^2+4x-5=0 \\ \\ delta 0 16+20 = 36 \\ \\ \sqrt{delta} = \sqrt{36}=6 \\ \\ x_{1} = \frac{-4+6}{2} =1 \\ \\ x_{2} = \frac{-4-6}{2} = -5[/latex] S={-5,1} [latex]c) \\ x(x+11)+2(x+21)=0 \\ \\ x^2+11x+2x+42=0 \\ \\ x^2+13x+42=0 \\ \\ delta= 169-4.42=1 \\ \\ \sqrt{delta} = \sqrt{1} = 1 \\ \\ x_{1} = \frac{-13+1}{2} = -6 \\ \\ x_{2} = \frac{-13-1}{2} = -7[/latex] S = {-7,-6} [latex]d) \\ 6(x^2-1)-14=5x^2+x \\ \\ 6x^2-6-14-5x^2-x=0 \\ \\ x^2-x-20=0 \\ \\ delta=1+80=81 \\ \\ \sqrt{81} =9 \\ \\ x_{1} = \frac{1+9}{2} = 5 \\ \\ x_{2} = \frac{1-9}{2} = -4[/latex] s= {-4,5}

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