Matemática
valeriano
11

3(x-4)/5=x-3/2 ??? Alguém pode me ajudar??

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(2) Respostas
jai05

Olá, 3(x-4)/5 = x-3/2 (3x-12)/5 = x-3/2 (3x-12) = 5·(x-3/2) (3x-12) = 5x-15/2 3x-5x = -15/2+12 -2x = (-15+24)/2 -2x = 9/2 x = (9/2)/-2 x = (9/2)/(-2/1) x = 9/2 · 1/-2 x = 9/-4 Resposta: -9/4

profcado

[latex]Se~~for~~dessa~~forma,~~x=9 ; \\\\\\ \dfrac{3(x-4)}{5} = \dfrac{x-3}{2} \to\\\\ \dfrac{3x-12}{5} = \dfrac{x-3}{2} \to~~~~ mmc=10 \\\\ 6x-24=5x-15\\\\ 6x-5x=-15+24\to\\\\ \large\boxed{x=9} [/latex] [latex]Se~~for~~dessa~~forma,~~x=- \dfrac{9}{4} ; \\\\\\ \dfrac{3(x-4)}{5} =x- \dfrac{3}{2} \to\\\\ \dfrac{3x-12}{5} =x- \dfrac{3}{2} \to~~~mmc=10\\\\ 6x-24=10x-15\to\\\\ 6x-10x=-15+24\to\\\\ -4x=9~.(-1)\to\\\\4x=-9\to\\\\ \large\boxed{x=- \dfrac{9}{4} } [/latex]

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