Write the equation of the line that passes through (–2, 1) and is perpendicular to the line 3x – 2y = 5.

3x - 2y = 5 2y = 3x - 5 y = (3/2) x - 5/2 so the gradient (m)  of the required line = -1 / (3/2) = -2/3 using the general form    y - y1 = m(x - x1)  ,                m = -2/3 , x1 = -2 and y1 = 1  y - 1 = -(2/3) ( x - (-2)) y = -(2/3)x - 4/3 + 1 y = -(2/3)x  - 1/3  multiply through by 3 3y = - 2x  - 1  in standard form its 2x + 3y = -1