Mathematics
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Write the equation of a line that is perpendicular to the line y=1/3X-7 and passes through the point (5,-2)

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bbb911

slope-intercept form of a line: y=mx+b m=slope other perpendicular line to this line (y=mx+b) will have the next slope: m´=-1/m We have this line in slope-intercet form: y=1/3x-7 m=1/3 A perpendicular line will have the next slope: m´=-1/m=-1(1/3)=-3 Now, we have a point (5,-2) and the slope (-3). point-slope form: given a point  (x₀,y₀) and the slope m, the point-slope form will be: y-y₀=m(x-x₀) In this case: y-(-2)=-3(x-5) y+2=-3x+15 y=-3x+15-2 y=-3x+13 Answer: The equation of a line (slope intercept form) that is perpendicular to the line y=1/3x-7 and passes throught the point (5,-2) is: y=-3x+13

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