Write the equation of a line that is perpendicular to the given line and that passes through the given point. 2x+9y=-30;(-8,0

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2x+9y=-30  subtract 2x from both sides 9y=-2x-30 divide both sides by 9 y=-2x/9-30/9 So the slope of the reference line is -2/9.  For a line to be perpendicular to this line their slopes must be negative reciprocals of one another, mathematically: m1*m2=-1 and in this case: -2m/9=-1 m=9/2 m=4.5, so far we have: y=4.5x+b, using point (-8, 0) we can solve for b 0=4.5(-8)+b 0=-36+b 36=b, so our line is: y=4.5x+36

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