Write the equation of a line in slope-intercept form that is perpendicular to the line y=3/5x-1 and passes through the point (-9, 4).
y = 3/5x - 1....slope here is 3/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So the slope we need is -5/3. y = mx + b slope(m) = -5/3 (-9,4)...x = -9 and y = 4 now we sub and find b, the y int 4 = -5/3(-9) + b 4 = 15 + b 4 - 15 = b - 11 = b so ur perpendicular line is : y = -5/3x - 11