Mathematics
Eskenazi573
21

write an equation of the line that passes through (8, -12) and is parallel to the line 3x + 4y=4

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(1) Answers
Hanington955

3x + 4y = 4 4y = -3x + 4 y = -3/4x + 1....slope here is -3/4. A parallel line will have the same slope. y = mx + b slope(m) = -3/4 (8,-12)...x = 8 and y = -12 now we sub and find b, the y int -12 = -3/4(8) + b -12 = - 6 + b -12 + 6 = b -6 = b so ur parallel equation is : y = -3/4x - 6 <== slope intercept form or if u need it in standard form : y = -3/4x - 6 3/4x + y = -6 3x + 4y = -24 <== standard form

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