Mathematics
katie24
18

Write an equation of the line that is perpendicular to 5x+20y=10 and passes through the point (8,3)

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(1) Answers
JosieG

5x+20y=10 20y=10-5x              /20 y=-1/4*x+1/2 a1=-1/4 a2=? a1*a2=-1 -1/4*a2=-1                  /(-1/4) a2=4 y=4x+b P(8,3) 3=4*8+b 3=32+b b=-29 y=4x-29 Regards M.Y.

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