tarahtackett
32

# Which value is equivalent to 7 multiplied by 3 multiplied by 2 whole over 7 multiplied by 5, the whole raised to the power of 2 multiplied by 7 to the power of 0 over 5 to the power of negative 3, whole to the power of 3 multiplied by 5 to the power of negative 9? 6 over 25 36 over 25 12 over 5 252 over 5

So, based on this, you would be doing $(( \frac{(7*3*2)}{(7*5)} )^2)*( \frac{(7^0)}{5^{-3}} )^3*(5^{-9})$ which would solve as follows: $(( \frac{(7*3*2)}{(7*5)} )^2)*( \frac{(7^0)}{5^{-3}} )^3*(5^{-9})=( \frac{6}{5} )^2*(125)^3*( \frac{1}{1953125} )$$=( \frac{36}{25} )*(1953125)*( \frac{1}{1953125} )= \frac{36}{25} =1.44$