What is the smallest positive value for x where y=sin2x reaches its maximum? How do you figure this out? ...?
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here. The amplitude of sin(x) is 1, so we want sin (2x) =1 taking inverse sin, we get 2x = [latex] \pi /2[/latex] divide by 2 and we get x = [latex] \pi /4[/latex]