What is the smallest positive value for x where y=sin2x reaches its maximum? How do you figure this out? ...?

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(1) Answers

hanan1

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The amplitude of sin(x) is 1, so we want
sin (2x) =1
taking inverse sin, we get
2x = [latex] \pi /2[/latex]
divide by 2 and we get
x = [latex] \pi /4[/latex]