What is the slope of the line defined by the equation 3x - y = 0?

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Well, to find the slope, you'd have to rearrange the equation so that it is in slope-intercept form, y=mx+b. 3x-y=0 -y=-3x+0 y=3x+0 The slope would be 3/1, and the line intersects y at point (0,0). Hope this helps :-)


The slope of the line is 3. First, solve the equation for y: [latex] 3x-y=0 \\ -y=-3x\\ y=3x [/latex] Slope-intercept form is where y = mx + b, where m is the slope and b is the y-intercept. Since m = 3, the slope of the line is 3.

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