What is the remainder when (x3 − 6x2 − 42x + 79) is divided by (x + 5)?

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(1) Answers

Czarny333

We can do synthetic division to solve this or just normal division. Either way, the remainder would be:
-406/(x+5)
The whole result is this:
(x3 − 6x2 − 42x + 79)/(x+5) = x2 - 11x +97 - 406/(x+5)
With the remainder as -406/(x+5)