Mathematics
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7

What is the relative maximum and minimum of the function? f(x) = 2x^2 + 28x - 8 A. Minimum Value: -106 Range y > -7 B. Minimum Value: -106 Range y > -106 C. Minimum Value: 7 Range y > 7 D. Minimum Value: -7 Range y > -7

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(1) Answers
steph2

We equate the derivative of the function to 0 to find the x-value at its minimum: f'(x) = 4x + 28 0 = 4x + 28 x = -7 Now, we put this value into the original equation to find the minimum value: f(-7) = -106 The function has a positive slope so it will increase. Thus, the range will be y > -106 The answer is B

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