Mathematics
Chirsthoper
59

What is the product? [latex] \frac{2a-7}{a}* \frac{3a^2}{2a^2-11a+14} [/latex] A. [latex] \frac{3}{a-2} [/latex] B. [latex] \frac{3a}{a-2} [/latex] C. [latex] \frac{3a}{a+2} [/latex] D. [latex] \frac{3}{a+2} [/latex]

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(2) Answers
kylaeberhardt92

The denominator of the second fraction can be factored as (a-2)(2a-7), then it becomes doable. You cancel the (2a-7) factors, and are left with: [latex]\frac{3a^2}{a(a-2)} \implies \frac{3a}{a-2} [/latex] Do note that you have erased the fact that a≠0 and a≠7/2, so you should always mention that.

rositaral73

B. 3a/a-2 im taking it

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