What is the percentages of Carbon, Hydrogen and oxygen in C6H12O6

First calculate the Ar of the compound.. ( Ar of C6H12O6 is 180) Then divide the At of the required element by 180 and multiply by 100...  so, for carbon 12 * 6 = 72 (THERE ARE 6 CARBON ATOM)                                (72/180) * 100 =40%     ITS THE SAME FOR THE OTHER 2 ELEMENT