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[latex]x^2-4x+3= \\ x^2-3x-x+3= \\ x(x-3)-1(x-3)= \\ (x-1)(x-3) \\ \\ \boxed{y=(x-1)(x-3)}[/latex]

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(1) Answers

[latex]x^2-4x+3= \\ x^2-3x-x+3= \\ x(x-3)-1(x-3)= \\ (x-1)(x-3) \\ \\ \boxed{y=(x-1)(x-3)}[/latex]

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