What is the equation of the line that passes through the point (6, 1) and is perpendicular to the line y = –3x + 2 a) y = –3x + 3 b) y = –3x – 9 c) y = x – 1 d) y = x + 19

The slope of the given equation of the line, y = -3x + 2 is equal to -3. The slope of the line perpendicular to it is 1/3. The equation of the line may be expressed in slope-point form which can generally be expressed as,                                y - y1 = m(x - x1) Substituting the values,                                y - 6 = (1/3)(x - 1)  Simplifying,                                  y = x/3 +17/3 The answer is not among the choices.