Mathematics
aiyanafrench
29

What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)?

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(2) Answers
Jlo13

First find slope: m = dy/dx m = 4/-4 m = -1 Then plug it into the Slope-intercept form is y - y1 = m(x - x1) Use either set of coordinates (We're using (3, -1) for this example) y - (-1) = -1(x - 3) y + 1 = -x + 3

Carry751

[latex]m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{5 - (-1)}{-1 - 3} = \frac{5 + 1}{-4} = \frac{6}{-4} = \frac{3}{-2} = -1\frac{1}{2}[/latex]    y - y₁ = m(x - x₁) y - (-1) = -1¹/₂(x - 3)    y + 1 = -1¹/₂(x) + 1¹/₂(3)    y + 1 = -1¹/₂x + 4¹/₂        - 1              - 1          y = -1¹/₂x + 3¹/₂

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