Mathematics
marialiu
30

What is the equation of a line that is perpendicular to y=3x-2 and passes through the point (6,8)

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(1) Answers
KatriceLaigo

y = 3x - 2.....the slope here is 3 or 3/1. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So we would need -1/3 as our perpendicular slope. y = mx + b slope(m) = -1/3 (6,8)...x = 6 and y = 8...we will be solving for b, the y intercept now we sub 8 = -1/3(6) + b 8 = - 1/2 + b 8 + 1/2 = b 16/2 + 1/2 = b 17/2 = b so ur perpendicular line is : y = -1/3x + 17/2

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