Mathematics
ecjbeer
35

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)?

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(2) Answers
jasminemcdonald

(-2,-4)(2,2) slope = (2+4)/(2+2) = 6/4 = 3/2 the equation, in point-slope form y - y1 = m(x - x1) so equation, passes through the point (−3, 1) y - 1 = 3/2(x + 3) answer  y - 1 = 3/2(x + 3)

Hanington955

(2,2)(-2,-4) slope = (-4 - 2) / (-2 - 2) = -6 / -4 = 3/2....slope of given line is 3/2...a parallel line will have the same slope y = mx + b slope(m) = 3/2 (-3,1)....x = -3 and y = 1 now we sub and find b, the y int 1 = 3/2(-3) + b 1 = -9/2 + b 1 + 9/2 = b 2/2 + 9/2 = b 11/2 = b so ur parallel equation is : y = 3/2x + 11/2

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