Two urns contain white balls and yellow balls. The first urn contains 3 white balls and 6 yellow balls and the second urn contains 3 white balls and 8 yellow balls. A ball is drawn at random from each urn. What is the probability that both balls are white?
We have 3 white balls in the first urn out of 9. That means we have a 1 in 3 chance at picking the white ball in the first urn. Now, we have a 3 in 11 chance at picking the white ball in the second urn. Since, we want them simultaneously, we need to multiply them. 1/3 × 3/11 = 1/11 chance
3×8×3×6=432 its this answer because im right you have times three and eight and times three plus six