Two natural numbers differ by 4 and the sum of their squares is 58 find the numbers?
The firs number: a The second number: b a-b=4 a²+b²=58 Lets write b+4 instead of a. (b+4)² + b² = 58 b²+8b+16+b²=58 2b²+8b+16=58 2b²+8b-42=0 b²+4b-21=0 (b+7).(b-3)=0 b=-7 or b=3 But, b can't equal to -7 because these number are naturel numbers. It must be positive. b=3 for b=3; a-3=4; a=7