Two cars leave a town at the same time heading in opposite directions. One car is travelong 12 mph faster than the other. After 2 hours, they are 232 miles apart. What is the speed of each car
d=vt+(v+12)t d=vt+vt+12t d=2vt+12t d=2t(v+6), and we are told that d=232 and t=2 2(2)(v+6)=232 4(v+6)=232 v+6=58 v=52 So the slower car is travelling at 52 mph and the faster car is traveling at 64 mph.