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# The value of y is inversely proportional to the value of x. When y=42, x=6. What is the value of y when x = 9?

Because $x$ and $y$ are inversely proportional, there is some constant $k$ such that $xy=k$ Given that $y=42$ and $x=6$, we have $k=6\times42=252$ So when $x=9$, you have $9y=252\implies y=\dfrac{252}9=28$