Mathematics
miguelelgetonnavarro
25

The population of a city is growing at an average rate of 3% per year. In 1990 , the population was 45000

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(2) Answers
rch9mcca

P(y)=450000(1.03)^(y-1990)

LashaunTrolinger984

a. N(y) = 45,000*1.03^(y-1990) N(y) = population in year y, 45,000 = poppulation in 1990, 1.03 = yearly growth factor, y = year y b. 2,007−1,990=17 years N(17)=45,000×1.03^(17)=74,378.14 c. 2N=N*1.03^ t 2=1.03^t t=log(2)÷log(1.03)=23.4 23.4+1,990=2,013.4 d. 2=(1+r)^10 r=2^(1/10)-1)*100=7.18%

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