Lilsto2002
31

The length of one leg of a right triangle is 24 feet and the length of the hypotenuse is 40 ft what is the length of the other leg

To solve for the other leg, you need to use Pythagorean theory. The theory states that C^2 = A^2 + B^2 In your case, you have to solve for B. C = 40 (hypotenuse)   A = 24 (leg 1) The formula rewritten for B is $b= \sqrt{c^{2}-a^{2} }$ Now, you can solve. $b= \sqrt{c^{2}-a^{2} } b= \sqrt{40^{2}-24^2 } b = \sqrt{1600 - 576} b = \sqrt{1024} b = 32$ Therefore, B = 32. So the second leg is 32 feet.