The length of one leg of a right triangle is 24 feet and the length of the hypotenuse is 40 ft what is the length of the other leg

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To solve for the other leg, you need to use Pythagorean theory. The theory states that C^2 = A^2 + B^2 In your case, you have to solve for B. C = 40 (hypotenuse)   A = 24 (leg 1) The formula rewritten for B is [latex]b= \sqrt{c^{2}-a^{2} }[/latex] Now, you can solve. [latex]b= \sqrt{c^{2}-a^{2} } b= \sqrt{40^{2}-24^2 } b = \sqrt{1600 - 576} b = \sqrt{1024} b = 32[/latex] Therefore, B = 32. So the second leg is 32 feet.

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