the length of a rectangle is five times its width. If the perimeter of the rectangle is 60 m , find its area.

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(2) Answers

alejandraperez

Suppose that l is the length and w is the width. l = 5w and 2l + 2w = 60.
You can substitute l in the second equation for 5w because the first equation says they're equal. 2(5w) + 2w = 60. 10w + 2w = 60. 12w = 60. w = 5. Put this value of w into the first equation. l = 5(5). l = 25. The area is l*w which is 5*25 = 125.

Peick965

length=x
width=y
we can suggest this system of equations:
x=5y
2x+2y=60
we can solve this system of equations by substitution method.
2(5y)+2y=60
10y+2y=60
12y=60
y=60/12=5
Now, we can find out the value of "x";
x=5y
x=5(5)=25
The length is 25 m, and the width is 5 m.
Area=lenght x width
Therefore:
Area=25 m * 5 m=125 m².
Answer: the area is 125 m²
Area=