Chemistry
DanaeDelrosario25
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The charges on two metallic balls are 5.0 and 7.0 coulombs respectively. They are kept 1.2 meters apart. What is the force of interaction between the two? (k = 9.0 × 109 newton·meters2/coulomb2) 2.2 × 1011 newtons 4.1 × 10-7 newtons 5.0 × 1011 newtons 7.0 × 10-7 newtons

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jfivnckx

Using Coulomb's Law, which states that F = kq1q2/r^2, where q1 and q2 are the charges of the objects, and r is the distance between them, we substitute: F = (9.0x10^9)(5.0)(7.0)/1.2² F = 2.1875x10^11 N Answer is 2.2 x 10^11 N.

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