Thiglife
3

# solve for (x-4)^2=13

$(x-4)^2=13$  First take the square root of both sides.  $x-4= \sqrt{13}$, $- \sqrt{13}$. There are two solutions because a square root comes with a positive and negative solution. Now move the 4 over by adding 4 on both sides.  $x= \sqrt{13}+4$, $- \sqrt{13} +4$