Mathematics
mloublue17
53

solve for the system of linear equations x+y=4 2x+3y=0

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(2) Answers
TamaraMundorf

x+y=4 2x+3y=0 x=4-y 2(4-y)+3y=0 8-2y+3y=0 8+y=0 y=-8 x+(-8)=4 x-8=4 x=12

lotusblossom5

solve x+y=4 for x x+y+-y=4+-y(add -y to both sides) x=-y+4 substitute -y+4 for x in 2x+3y=0 2x+3y=0 2(-y+4)+3y=0 y+8=0(simplify both sides of the equation) y+8+-8=0+-8(add -8 to both sides) y=-8 substitute -8 for y in x=-y+4: x=-y+4 x=-(-8)+4 x=12(simplify both sides of the equation) answer is x=12 and y=-8

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