Solve algebraically 3^x= 243

3^x=243 so : ³log243=x ³log 3^5=x x=5 or 5^√243 =3

[latex]3^{x} = 243 \\ln(3^{x}) = ln(243) \\xln(3) = ln(243) \\\frac{xln(3)}{ln(3)} = \frac{ln(243)}{ln(3)} \\x = \frac{ln(243)}{ln(3)} \\x = \frac{ln(3^{5})}{ln(3)} \\x = \frac{5ln(3)}{ln(3)} \\x = 5[/latex]