Mathematics
joneslianna9
37

PLEASE HELP!!!!!! solve for the equations : - 3y + 7 + 3(y-1) = 2(2y+6) - (x-5)(x+4) = (x+7)(x-6) - 2(x+1)2(x-2)2 = x(x-3)

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(2) Answers
andrades

-3y + 7 + 3(y - 1) = 2(2y + 6) -3y + 7 + 3y - 3 = 4y + 12 4y = 4 - 12 = -8 y = -8/4 = -2. -(x - 5)(x + 4) = (x + 7)(x - 6) -(x^2 + 4x - 5x - 20) = x^2 - 6x + 7x - 42 -x^2 + x + 20 = x^2 + x - 42 2x^2 = 62 x^2 = 62/2 = 31 [latex]x=\pm\sqrt{31}[/latex]

JayQueline

1.y=-2 2. x1,2=+-5.56 3.x1=16.13 , x2=-0.85

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