(2) Answers
just subtract them 4-4=0 9-3=6 the distance is 6 since the x part stayed on the sam line
[latex]d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\ d=\sqrt{(4-4)^2+(9-3)^2}\\ d=\sqrt{0^2+6^2}\\ d=\sqrt{6^2}\\ d=6[/latex]
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just subtract them 4-4=0 9-3=6 the distance is 6 since the x part stayed on the sam line
[latex]d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\ d=\sqrt{(4-4)^2+(9-3)^2}\\ d=\sqrt{0^2+6^2}\\ d=\sqrt{6^2}\\ d=6[/latex]