Chemistry
Jazz1
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In the same reaction HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l), if 125.0 milliliters of a 1.5 M HCl react in with 87.5 milliliters of 1.75 M NaOH, how many grams of H2O will be produced?

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(1) Answers
sierraf

1) Chemical reaction HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l), 2) Molar ratios 1 mol HCl : 1 mol NaOH : 1 mol NaCl : 1 mol H2O 3) Find the number of moles of each reactant 125.0 milliliters of a 1.5 M HCl M = n / V => n = M * V = 1.5 M * 0..1250 l = 0.1875 mol HCl 87.5 milliliters of 1.75 M NaOH, n = M*V = 1.75 M * 0.0875 l = 0.1531 mol NaOH 3) Limiting reagent It is NaOH because its 0.1531 moles will be consumed before the 0.1875 mol of HCl are depleted. 4) Use molar ratios to determine the number of moles of H2O produced: 1:1 => 0.1531 mole of H2O 5) how many grams of H2O will be produced? use the molar mass to convert 0.1531 mol of H2O to grams: 0.1531 mol * 18.0 g / mol = 2.76 g Answer: 2.76 g

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