Chemistry
Jazz1
22

In the reaction HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l), if 45.0 milliliters of a 2.0 M HCl react in an excess of NaOH, how many grams of H2O will be produced?

+2
(1) Answers
sierraf

1) Chemical equation HCl (aq) + NaOH (aq) --> NaCl (aq) + H2O (l) 2) Molar ratios 1 mol HCl : 1 mol NaOh : 1 mol NaCl : 1 mol H2O 3) Number of moles of HCl: M = n / V => n = M * V = 2.0M * 0.045 l = 0.09 mol 4) Use the adequate proportion: 1mol HCl / 1 mol H2O = 0.09 mol HCl / x => x = 0.09 mol H2O 5) Use the molar mass of H2O to convert moles to grams => 0.09 mol * 18.0 g/mol = 1.62 g Answer: 1.62 g

Add answer