Chemistry
2019cgage
9

If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

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(1) Answers
smiggles

Okay so according to the formula PV=nRT n=4 P=5.6 atm V=12 L R=0.08206 L atm mol-1 K-1 T=? So, if you plug it in, you will get:- T=PV/nR T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1) T=204.73 K Hope I'm right! :)

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