If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?

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(1) Answers

smiggles

Okay so according to the formula PV=nRT
n=4
P=5.6 atm
V=12 L
R=0.08206 L atm mol-1 K-1
T=?
So, if you plug it in, you will get:-
T=PV/nR
T=(5.6 atm)(12 L)/(4 mol)(0.08206 L atm mol-1 K-1)
T=204.73 K
Hope I'm right! :)