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# if f(x)=x^2-5x+3 then what is the value of f(x-1)

$f\left( x \right) ={ x }^{ 2 }-5x+3$ The value of $f(x-1)$ is wanted. To find it, we'll plug x-1 in the function of f(x). $f\left( x \right) ={ x }^{ 2 }-5x+3\\ \\ f(x-1)=\quad { (x-1) }^{ 2 }-5(x-1)+3\\ \\ f(x-1)=\quad { x }^{ 2 }-2x+1-(5x-5)+3\\ \\ f(x-1)=\quad { x }^{ 2 }-2x+1-5x+5+3\\ \\ f(x-1)=\quad { x }^{ 2 }-2x-5x+1+8\\ \\ f(x-1)=\quad { x }^{ 2 }-7x+9\quad$