(1) Answers
[latex]f\left( x \right) ={ x }^{ 2 }-5x+3[/latex] The value of [latex]f(x-1)[/latex] is wanted. To find it, we'll plug x-1 in the function of f(x). [latex]f\left( x \right) ={ x }^{ 2 }-5x+3\\ \\ f(x-1)=\quad { (x-1) }^{ 2 }-5(x-1)+3\\ \\ f(x-1)=\quad { x }^{ 2 }-2x+1-(5x-5)+3\\ \\ f(x-1)=\quad { x }^{ 2 }-2x+1-5x+5+3\\ \\ f(x-1)=\quad { x }^{ 2 }-2x-5x+1+8\\ \\ f(x-1)=\quad { x }^{ 2 }-7x+9\quad [/latex]
Add answer
Sign in
Sign up