if a ball was thrown upward at 46.3 m/s how long would the ball stay in the air

[latex]V = Vo + a.t [/latex] The ball is against the vector of gravity. Then, the gravity will be negative. [latex]0 = 46,3 + (-9.8).t \\ t = \frac{46.3}{9.8} \\ t \approx 4.72 [/latex] The ball will stop in the air after approx. 4.72 seconds. And will take the same time to hit the ground. It will stay approx. 9.44 seconds in the air.