Mathematics
terrydavis1206
39

I have some idea about how to solve this but I am not sure So please show your work

+3
(1) Answers
monicabaugh

nPr=[latex] \frac{n!}{(n-r)!} [/latex] 9P3=[latex] \frac{9!}{(9-3)!} [/latex]= 9!/6!=(9*8*7*6*5*4*3*2*1)/(6*5*4*3*2*1) cancel= (9*8*7)/(1)=504 ways nCr=[latex] \frac{n!}{r!(n-r)!} [/latex] 10C4=[latex] \frac{10!}{4!(10-4)!} [/latex]= [latex] \frac{10!}{4!(6)!} [/latex]= [latex] \frac{10*9*8*7*6*5*4*3*2*1}{4*3*2*1*6*5*4*3*2*1} [/latex], cancel= [latex] \frac{10*9*8*7}{4*3*2*1} [/latex]= [latex] \frac{2*5*3*3*2*4*7}{4*3*2*1} [/latex]= [latex] \frac{5*3*2*7}{1} [/latex]=210

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