Chemistry
Kimaniwallace
3

How many mL of a 4% mass/volume Mg(NO3)2 solution would contain 1.2 grams of magnesium nitrate?

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(1) Answers
Lara14

4% mass / volume : 4 g ---------> 100 mL 1.2 g ------- ? mL V = 1.2 * 100 / 4 V = 120 / 4 V = 30 mL hope this helps!

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