how many grams of calcium bromide are in 50.0 ml of a 0.25 m calcium bromide solution

Molarity = n/Volume(L) n = Mass/Molar Mass => Molar Mass = 40.078 + 79.904 = 119.982g/mol Molarity = 0.25 Volume = 0.050 => n = 0.25*0.050 = 1.25e-2 (0.0125) Mass = n*Molar Mass = 1.25e-2*119.982 = 1.50g