Mathematics
yaritza
24

how do you solve the system of elimination method.x-6y=-30-2x-5y=-25

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(2) Answers
tuurajordan

x-6y=-30...equatn 1 -2x-5y=-25....equatn 2 multiply eqn 1 and 2 with 5 and 6 respectively 5x-30y=-150 -12x-30y=-150 subtract to eliminate y 17x=0 x=0 substitute x=0 into any of the equations 0-6y=-30 -6y=-30 y=-30/-6 y=5 x=0;y=5

lekshmi

x - 6y = -30 / * 2 -2x - 5y = -25 2x - 12y = -60 -2x - 5y = -25 -------------------- + 2x - 2x - 12y - 5y = -60 - 25 -17y = -85 / : (-17) y = 85/17 y = 5 y = 5 x - 6y = -30 y = 5 x - 6 * 5 = -30 y = 5 x - 30 = -30 y = 5 x = 30 - 30 y = 5 x = 0 answer: x = 0 y = 5

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