Mathematics
AntoinetteBeasley
39

How do you solve the equation 3x^2-10x=-8 by factoring?

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(2) Answers
pablodiablo

[latex]3x^2-10x+8=(3x-4)(x-2)=0[/latex] [latex]3x=4\lor x=2[/latex] [latex]x=\dfrac{4}{3}=1\dfrac{1}{3} \lor x=2[/latex]

Bowline347

Hi again! 3x² - 10x = -8 3x² - 10x + 8 = 0 Factorize (3x−4)(x−2)=0 Set factors equal to 0 3x - 4 = 0 or x- 2= 0 3x = 0 + 4 or x= 0 + 2 3x = 4 or x = 2 x = 4/3 or x = 2 Final answer : X = 4/3 or x = 2

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