Mathematics
maaax1
8

how do you solve for sinxcos2x+cosxsin2x=0 ?

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(2) Answers
haylerzzzz

LHS is nothing but (using sin (a+b) = sin a cos b + cos a sin b) sin (x+2x) = sin 3x = 0 so 3x = npi or x = npi/3

ruth26

The answer is x = n p i divided by 3

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