Mathematics
rrobinson2
37

How do you solve 3x+4y=12 and 2x=y-6

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(1) Answers
lilchop06

3x +4y =122x = y-6 Rewrite this as y = 2x+6 now replace that for y in the first equation3x + 4(2x+6) = 12now do all the calculations:3x + 8x +24 =1211x + 24 = 1211x = -12x = -12/11 = -1 1/11 now substitute -12/11 for x in the 2nd equation and solvey = 2x+6y = 2(-1 1/11) +6y = 42/11 = 3 9/11

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