Mathematics
Zayas
41

How do you factor and solve this equation? y^2-2y-8=7

+4
(1) Answers
Jayda

ok so set one side equal to zero by subtractin g7 now we have y^2-2y-15=0 if we factor then set each factor to zero we can solve becasue if we have xy=0 then assume x and y=0 so y^2-2y-15 find what 2 factors of -15 add to -2 -5 and 3 (x-5)(x+3) tada (x-5)(x+3)=0 x-5=0 add 5 x=5 x+3=0 subtract 3 x=-3 x=5 or -3

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